PRACTICA_MATES_18_9_25
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Alier 2025-09-18 13:53:52 +02:00
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commit d7d2b4b1d7
2 changed files with 29 additions and 148 deletions

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@ -58,6 +58,10 @@ Si $z = r(\cos \alpha + i \sin \alpha)$ y $\mu \in \mathbb{Z}$, entonces:
$$
\huge z^\mu = r^\mu \big(\cos(\mu \alpha) + i \sin(\mu \alpha)\big)
$$
O en forma polar:
$$
\huge z^\mu_{\alpha}=z^\mu_{\alpha\cdot\mu}
$$$
- Aquí $r = |z|$ es el módulo de $z$ y $\alpha = \arg(z)$ es el argumento.